How To Check A Campground Electric Service

Sizing RV-Park Electric Services Using NEC Table

By: | Oct 05, 2018

The Electrical Service supplying an entire RV park must be sized to accommodate the electric demands of multiple modern recreational vehicles cartoon power simultaneously from the individual park sites. The sum of the individual sites inside the park, with some additional math practical, determines the total service size for the park.

Per the 2017 NEC, when computing an RV park service, the load that you count for a single RV site equipped with a 125/250 volt, 50-ampere receptacle has been increased from 9600 volt-amperes to 12,000 volt-amperes.

The load yous count for a single RV site equipped with both 30-ampere and 20-ampere receptacles remains unchanged at 3600 volt-amperes. The load counted for a 20-ampere RV site receptacle is 2400 volt-amperes. And the load counted for each xx-amp supply provided at each dedicated tent site is 600 volt-amperes.

The individual RV sites within an RV park are equipped with "supply-equipment" then that the RVs tin connect to the available electrical. These individual supply enclosures typically consist of more than ane receptacle. When a multi-receptacle supply enclosure is defended to only a single RV, the load that you count toward determining the size of the entire park service is based on the single highest rated receptacle within that multi-receptacle enclosure. For example, if it contains a l-ampere as well equally a 20-ampere receptacle, you would only count the 50-ampere. Nevertheless, where the supply enclosure is expected to serve two recreational vehicles, the load you count toward sizing the park service is calculated using the two highest rated receptacles within that enclosure and not just the one.

After adding up the individual sites throughout the park, the next pace is to apply the need factors plant in Table 551.73(A). This Table allows for the derating of the park's service amps based on the full number of individual sites inside the park. For example: The demand factor for a service supplying just i RV site is 100%, which is but another way of saying that in that location is no commanded demand factor at all. But when at that place are 36 or more than sites in the park, the demand factor from the Tabular array is 41%, regardless of how many sites at that place are across 36. This means the park electrical service can be sized at an ampacity no greater than what is necessary to fairly supply merely 41% of the full load of 36 RV sites, instead of 100% for all 36 sites. This derating is permitted because the NEC assumes that all 36 sites won't exist occupied and in total utilize at the aforementioned time. Notation: The derated demand factors found in this Table are not practical to loads such as RV park bathrooms, recreational buildings, pond pools, or similar amenities. These loads are calculated separately.

Here is an RV Park Service Calculation Instance:

20 sites, and each site is equipped with:

I 50-ampere, 125/250-volt receptacle.

1 xxx-ampere, 125 volt receptacle.

One xx-ampere, 125 volt receptacle.

You just count the largest receptacle of the three, which is fifty-ampere: (twenty sites x 50 amp receptacles, worth 12,000 va each: xx x 12,000 = 240,000 VA)

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15 sites, and each site is equipped with:

One thirty-ampere, 125 volt receptacle.

1 20-ampere, 125 volt receptacle.

Remember, when both 20-ampere and 30-ampere receptacles are present at one site, the value is 3600VA: (xv sites 10 3600va = 54,000 VA)

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15 sites, and each is equipped with:

One 20-ampere, 125 volt receptacle.

A 20-ampere receptacle is worth 2400va: (15 sites x 2400va = 36,000 VA)

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10 sites for tent camping, each equipped with 20amps of ability:

Each tent site supplied with 20 amps, counts as 600va: (10 sites x 600va = 6000 VA )

TOTAL VA FOR THESE sixty SITES = 336,000 VA

Need Cistron from Tabular array 551.73(A) is 41 % for 36 or more than RV sites, and then 336,000 x 41% =137,760 VA

Finally: If the RV park'southward service is going to be 120/240 single phase, and so the minimum ampacity for that service would be determined by taking that 137,760 VA and dividing past 240 V = 574 AMPS

A 600 Amp service would exist adequate.